How to strip first digit in TO destination number

[jfcourteau@pixelweb.net]

1. Brekeke Product Name and Version: 2.4.8.6/286.3

2. Java version: 1.6.0_24

3. OS type and the version: Ubuntu Linux 10.10

4. UA (phone), gateway or other hardware/software involved: Asterisk PBX

5. Your problem: I'm trying to remove first digit in my dial-plan rule before sending the call to my customer (Asterisk)

Basically I want to remove the country code (1) and send only 10 digits to the customer...

Here is my current dialplan rule:

Matching Patterns

$request = ^INVITE $addr = 10.10.10.10 To = sip:(1819000000|18190000001|18190000002|18190000003)@ $regaddr( "user-sip" ) = (.+)

Deploy Patterns

$auth = false To = sip:%1@%2 $replaceuri.from = true $continue = false

How would I do this using a regex?

Thanks in advance.

[hope]

Matching Patterns

$request = ^INVITE $addr = 10.10.10.10 To = sip:1(819000000|8190000001|8190000002|8190000003)@ $regaddr( "user-sip" ) = (.+)

or

Matching Patterns

$request = ^INVITE $addr = 10.10.10.10 To = sip:1(81900000[0-3])@ $regaddr( "user-sip" ) = (.+)

remove 1 before number 819000000-819000003

http://rubular.com/

[jfcourteau@pixelweb.net]

Thanks a lot works perfectly.